(Not exactly sure what your question means, but I hope that this answers it. I think that you are asking about the ionic formula for lead(ii) oxide?)

A Lead(ii) ion means that the ion is ##Pb^(2+)## -with a 2+ charge. (and when you see lead(iv), it has a ##Pb^(4+)## ion)

The equation:

##Pb^(2+)## + ##O^(2-)#### ->## ##PbO##

lead(ii) ion + oxygen ion ##->## lead(ii) oxide.

(If it was lead(iv) oxide, this would be the equation: ##Pb^(4+)## + ##2O^(2-)#### ->## ##PbO_2##)